Optimal. Leaf size=114 \[ \frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {f x^m}{e}\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {f x^m}{e}\right )}{m}+\frac {b k n \text {Li}_3\left (-\frac {f x^m}{e}\right )}{m^2} \]
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Rubi [A]
time = 0.12, antiderivative size = 114, normalized size of antiderivative = 1.00, number of steps
used = 4, number of rules used = 4, integrand size = 26, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.154, Rules used = {2422, 2375,
2421, 6724} \begin {gather*} -\frac {k \text {PolyLog}\left (2,-\frac {f x^m}{e}\right ) \left (a+b \log \left (c x^n\right )\right )}{m}+\frac {b k n \text {PolyLog}\left (3,-\frac {f x^m}{e}\right )}{m^2}+\frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {k \log \left (\frac {f x^m}{e}+1\right ) \left (a+b \log \left (c x^n\right )\right )^2}{2 b n} \end {gather*}
Antiderivative was successfully verified.
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Rule 2375
Rule 2421
Rule 2422
Rule 6724
Rubi steps
\begin {align*} \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (d \left (e+f x^m\right )^k\right )}{x} \, dx &=\frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {(f k m) \int \frac {x^{-1+m} \left (a+b \log \left (c x^n\right )\right )^2}{e+f x^m} \, dx}{2 b n}\\ &=\frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {f x^m}{e}\right )}{2 b n}+k \int \frac {\left (a+b \log \left (c x^n\right )\right ) \log \left (1+\frac {f x^m}{e}\right )}{x} \, dx\\ &=\frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {f x^m}{e}\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {f x^m}{e}\right )}{m}+\frac {(b k n) \int \frac {\text {Li}_2\left (-\frac {f x^m}{e}\right )}{x} \, dx}{m}\\ &=\frac {\left (a+b \log \left (c x^n\right )\right )^2 \log \left (d \left (e+f x^m\right )^k\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right )^2 \log \left (1+\frac {f x^m}{e}\right )}{2 b n}-\frac {k \left (a+b \log \left (c x^n\right )\right ) \text {Li}_2\left (-\frac {f x^m}{e}\right )}{m}+\frac {b k n \text {Li}_3\left (-\frac {f x^m}{e}\right )}{m^2}\\ \end {align*}
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Mathematica [B] Leaf count is larger than twice the leaf count of optimal. \(277\) vs. \(2(114)=228\).
time = 0.12, size = 277, normalized size = 2.43 \begin {gather*} -\frac {1}{6} b k m n \log ^3(x)-\frac {1}{2} b k n \log ^2(x) \log \left (1+\frac {e x^{-m}}{f}\right )+b k n \log ^2(x) \log \left (e+f x^m\right )-\frac {b k n \log (x) \log \left (-\frac {f x^m}{e}\right ) \log \left (e+f x^m\right )}{m}-b k \log (x) \log \left (c x^n\right ) \log \left (e+f x^m\right )+\frac {b k \log \left (-\frac {f x^m}{e}\right ) \log \left (c x^n\right ) \log \left (e+f x^m\right )}{m}-\frac {1}{2} b n \log ^2(x) \log \left (d \left (e+f x^m\right )^k\right )+\frac {a \log \left (-\frac {f x^m}{e}\right ) \log \left (d \left (e+f x^m\right )^k\right )}{m}+b \log (x) \log \left (c x^n\right ) \log \left (d \left (e+f x^m\right )^k\right )+\frac {b k n \log (x) \text {Li}_2\left (-\frac {e x^{-m}}{f}\right )}{m}+\frac {k \left (a-b n \log (x)+b \log \left (c x^n\right )\right ) \text {Li}_2\left (1+\frac {f x^m}{e}\right )}{m}+\frac {b k n \text {Li}_3\left (-\frac {e x^{-m}}{f}\right )}{m^2} \end {gather*}
Antiderivative was successfully verified.
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Maple [F]
time = 0.03, size = 0, normalized size = 0.00 \[\int \frac {\left (a +b \ln \left (c \,x^{n}\right )\right ) \ln \left (d \left (e +f \,x^{m}\right )^{k}\right )}{x}\, dx\]
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Failed to integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A]
time = 0.37, size = 173, normalized size = 1.52 \begin {gather*} \frac {b m^{2} n \log \left (d\right ) \log \left (x\right )^{2} + 2 \, b k n {\rm polylog}\left (3, -f x^{m} e^{\left (-1\right )}\right ) + 2 \, {\left (b m^{2} \log \left (c\right ) + a m^{2}\right )} \log \left (d\right ) \log \left (x\right ) - 2 \, {\left (b k m n \log \left (x\right ) + b k m \log \left (c\right ) + a k m\right )} {\rm Li}_2\left (-{\left (f x^{m} + e\right )} e^{\left (-1\right )} + 1\right ) + {\left (b k m^{2} n \log \left (x\right )^{2} + 2 \, {\left (b k m^{2} \log \left (c\right ) + a k m^{2}\right )} \log \left (x\right )\right )} \log \left (f x^{m} + e\right ) - {\left (b k m^{2} n \log \left (x\right )^{2} + 2 \, {\left (b k m^{2} \log \left (c\right ) + a k m^{2}\right )} \log \left (x\right )\right )} \log \left ({\left (f x^{m} + e\right )} e^{\left (-1\right )}\right )}{2 \, m^{2}} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F(-2)]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {Exception raised: TypeError} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F]
time = 0.00, size = 0, normalized size = 0.00 \begin {gather*} \text {could not integrate} \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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Mupad [F]
time = 0.00, size = -1, normalized size = -0.01 \begin {gather*} \int \frac {\ln \left (d\,{\left (e+f\,x^m\right )}^k\right )\,\left (a+b\,\ln \left (c\,x^n\right )\right )}{x} \,d x \end {gather*}
Verification of antiderivative is not currently implemented for this CAS.
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